CODE
[code]
$sql = "SELECT * FROM membres WHERE login=$login and pass=$pass";
$res = mysql_query($sql);
$exist = mysql_numrows($res);
$sql = "SELECT * FROM membres WHERE login=$login and pass=$pass";
$res = mysql_query($sql);
$exist = mysql_numrows($res);
et y me renvoit sa :
CODE
Warning: mysql_numrows(): supplied argument is not a valid MySQL result resource in c:program fileseasyphpwwwwwwjv2004pageidentifier.php on line 5
[ita]*** Message édité par Klandestino le 21/09/2003 11:35 ***[/ita]